Hi,

Pasting from faq:

Q) How to debug no records (blank grid)?

Few considerations before use

1) include the jqgrid_dist.php file before any thing rendered to output.
2) Check the ajax response of grid,

Also make sure, you call '$g->render();' function before any HTML is rendered
(echo'd) to output, as it expect exact JSON format for ajax calls

Use firefox->firebug->net->ajax-call of grid->response. You will see the output there, in case of any error. It should be proper JSON format data in order to render grid

Review this tutorial for '[debugging with firebug](https://phpgrid.desk.com/customer/portal/articles/926266)'.

To enable debugging errors,

1) Turn errors on. Goto jqgrid_dist.php make it 'on'

ini_set("display_errors","on"); // changed from off to on

2) If you are using non-mysql database, Goto file jqgrid_dist.php

$g = new jqgrid($db);
…
$g->con->debug = 1; // changed from 0 to 1r