I found the line of code that causes the error. It looks like the $field variable is just the column name and not the table + column. I don't know if there is a way to pass the table and then concat the two??

$qwery .= "LOWER($field)".$qopers[$op]." LOWER(".$v.")";

Also, I found that if you use the select_command and use the select * from (MY STATEMENT) as o, this breaks the in-line search. It doesn't have the proper format for sql. I had to go through and take those out.

Hello

All you need is to use following with column definition. This will resolve the name conflict for searching.

$col["dbname"]="table.field";

Ok, so that would require me to setup the columns manually and not use the auto-populate option, like I am currently using. I will give it a try.

Yes, it is not doable with auto-populate option. You have to go manual way.

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