Montemaggiore Sebastian asked 9 years ago
Hello Abu. I saw the example in ../demos/master-detail/subgrid.php and subgrid_detail.php and i coludn´t undestand why in subgrid_detail.php you use
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jQuery('#<?php echo $g->id?>').jqGrid('navButtonAdd', '#<?php echo $g->id?>_pager',
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instead of something like
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jQuery('#aperturas').jqGrid('navButtonAdd', '#aperturas_pager',
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The case is that i want to put a custom button in the toolbar of the subgrid and my code does not show the button.
I put my code in pastebin:
Master-Grid —> http://pastebin.com/gP97pvL8
Sub-Grid ——> http://pastebin.com/fQ8veiUq
Can you help me?.
Montemaggiore Sebastian answered 9 years ago
Hello Abu.
I forgot I had this question. Of course it's silly . There are many subgrillas and how to identify it is through his relation id
jQuery ('# < ? Php echo $ g- > id ? >' ) . JqGrid ( ' navButtonAdd ' '# < ? Php echo $ g – > id > _ pager ' ?
I worked late and sleep played a trick on me .
Abu Ghufran answered 9 years ago
Each subgrid has different id based on parent row that is expanded. You can get it $g->id.
