Richard asked 12 years ago
I have a store locator. Some stores (a very small proportion) have their own home page. I would like to create a hyperlink on the store name in those cases where a hyperlink exists, but leave the others unmarked.
Is this possible?
Abu Ghufran answered 12 years ago
Yes, it is possible using 'conditional cell data' feature. Little modification required in lib jqgrid_dist.php
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$row[$col_name] = ( $r ? $c["default"] : '');
and replace with
$row[$col_name] = ( $r ? $c["default"] : $row[$col_name]);
Now, in column definition…
$col = array();
$col["title"] = "Company";
$col["name"] = "company";
$col["width"] = "30";
$col["align"] = "center";
$buttons_html = "<a target='_blank' href={website}'>{company}</a>"; // where website and company both are cols of grid.
$col["default"] = $buttons_html;
// use single quote for condition, and $row will have all columns data, to use in condition
$col["condition"] = '$row["website"] != ""';
$cols[] = $col;
Richard answered 12 years ago
$buttons_html = "<a target='_blank' href={website}'>{company}</a>";
should be
$buttons_html = "<a target='_blank' href='{website}'>{company}</a>";
… but even so, there are 2 issues:
1. The company field is url encoded (showing + instead of spaces). I have tried to fix this both by using the built in php urldecode function and str_replace("+"," ","{company}") but neither removes the +.
2. The website link is part of the data returned via $g-select_command = $SQL; but I have not put it in the grid. It does work (sort of) when I add it to the grid, but I have not worked out how to hide the column (as I don't want it displayed).
The other problem is that the link appears like this:
http://www.mywebsite.com/http%3A%2F%2Fwww.storewebsite.com
Abu Ghufran answered 12 years ago
For html encoded data, use this formatter for company and website.
$col["formatter"] = "function(cellval,options,rowdata){return $.jgrid.htmlEncode(cellval);}";
Youcan hide website column using
$col["hidden"] = true;
