Lacroix Alexis asked 10 years ago
Hello,
I'm using PHP GRID CONTROL on a webpage. On this webpage I can change a parameter to filter the datas in the table. I'm using a POST form which calls back the same webpage. She retrieve the POST data and she's uses it in the $g->select_command.
But the table don't take care of this new data. It's the same result as before I changed the parameter …
How I retrieve the POST data :
if ((isset($_POST['site'])) && (!empty($_POST['site']))) {
$_SESSION['site'] = $_POST['site'];
}
$site = $_SESSION['site'];
My SQL command : $g->select_command = "SELECT s.`ref`,s.`quantite`,s.`rupture` FROM `stock` s LEFT JOIN `produits` p ON s.`ref`= p.`ref` WHERE s.`date` ='".$date."' AND p.`site` = '".$site."'";
(It works for $date because I'm searching this data in the SQL database)
PS : I looked the FAQ, question : How to load grid based on $_POST data from other page?
But it doesn't works…
Where should we write the code given in the FAQ ? Before the include("phpgrid-free-v1.5.2/lib/inc/jqgrid_dist.php"); ??
Best Regards,
Alexis
Lacroix Alexis answered 10 years ago
EDIT : It's working now but when I'm leaving the webpage and if I'm coming back it keeps the last data from $site.
So I tried to add : else { $_SESSION['site'] = "EBC"; }
to make that when we come back $site = "EBC" but in this case the table show only when $site = "EBC" not the other possibility …
Abu Ghufran answered 10 years ago
1) Yes, conditional formatting is part of licensed version
2) You can put select_command (sql) and add WHERE condition to show only rows that have column value != 0.
Lacroix Alexis answered 10 years ago
REEDIT : Sorry for triple post…
I've change the method, I use 2 links which uses GET method. It's working now.
But the research of the table don't works now … :/
I have this error :
Couldn't execute query. Column 'ref' in where clause is ambiguous – SELECT count(*) as c FROM (SELECT s.`ref`,s.`quantite`,s.`rupture` FROM `stock` s LEFT JOIN `produits` p ON s.`ref`= p.`ref` WHERE s.`date` ='2014-12-09' AND p.`site` = 'EBC' AND ref LIKE '%2874%') pg_tmp
What is the problem ?
Lacroix Alexis answered 10 years ago
REREEDIT : I've solved this problem, but now I would like give a css property to a row. For this we should use "Conditionnal Formating", I tried but i've a blank page… "Conditionnal Formating" is working with free version ?
Second question : Could we do a condition for the row display ? Per example if the value of a column from this row is equal to 0, the grid shouldn't display this row.
Thanks for responses 🙂
