You need to do it via little JS code

To get selected row id,

var selr = jQuery('#list1').jqGrid('getGridParam','selrow');
if(selr) alert(selr);
else alert("No selected row");
return false;

To get multiple rows selected,

var selr = jQuery('#list1').jqGrid('getGridParam','selarrrow');
if(selr) alert(selr);

Where list1 is the param passed when rendering grid.

// generate grid output, with unique grid name as 'list1'
$out = $g->render("list1");

ok, I have done this,
Now the character of the grid is greater,

// render grid
$out = $g->render("list1");

?>

<script type="text/javascript">
var selr = jQuery('#list1').jqGrid('getGridParam','selrow');
if(selr) alert(selr);
else alert("No selected row");
return false;
</script>

$id_riparazione = ???? how do I get id of the selected record in the grid?

$result = mysql_query("SELECT CLIENTE, MARCA, MODELLO, SERIALE, DIFETTO, DIFETTODICHIARATO, NUMERO, RIVENDITORE
FROM schederivenditori WHERE IDRIPARAZIONE = $id_riparazione");

thanks and good day

If you want to have master-detail bahavior, that selecting parent grid will reflect change in sub grid … this example is covered in master-detail.php in package.

Emailing you in another thread.

the example you gave me does not work, if I comment this code table data client, otherwise I do not see anything, and then when I select the row nothing appears in list2

//if ($non_ajax || $_REQUEST["grid_id"] == "list1")

if ($non_ajax || $_REQUEST["grid_id"] == "list1") ……….. this check is necessary for 2 grids on same page.

Is the multiple-grid,php file working when placed in package?

Thanks